A.16
B.32
C.40
D.80
[单选题]现有如下程序段#include "stdio.h"int *fun(int *a,int *b){int c;c=*a%*b;return &c;}main(){int a=5,b=19,*c;c=fun(&a,&b);printf("%d\n",++*c);}则程序段执行后的结果为A.8B.7C.6D.5
[单选题]有如下程序#include "stdio.h"void fun(int *a,int *b){ int m; m=(*a+*b)*(*a+*b); m+=(*a-*b)*(*a-*b); printf("%d\n",m);}main(){ int a=5,b=6,*x=&a,*y=&b; fun(x,y);}程序执行后输出的结果为A.120 B.121 C.122 D.123
[单选题]有如下程序段#include "stdio.h"void fun(int *a,int *b,int *c,int *d,int *e){ int i,j,k,m; for(i=0;i< *a;i++) for(j=0;j< *b;j++) for(k=0;k<*c;k++) for(m=0;m< *d;m++) ++*e;}main(){ int a=10,b=10,c=10,d=10,e=0; fun(&a,&b,&c,&
[单选题]有如下程序#include "stdio.h"main(){ int a,b,m; for(a=5;a>=1;a--) { m=0; for(b=a;b<=5;b++) m=m+a*b; } printf("%d\n",m);}上述程序的运行结果是A.30 B.15 C.20 D.10
[单选题]现有如下程序段#include "stdio.h"main(){ int k[30]={12,324,45,6,768,98,21,34,453,456};int count=0,i=0;while(k[i]){ if(k[i]%2==0||k[i]%5==0)count++;i++; }printf("%d,%d/n",count,i);}则程序段的输出结果为A.7,8B.8,8C.7,10D.8,10
[单选题]现有如下程序段#include "stdio.h"main(){ int k[30]={12,324,45,6,768,98,21,34,453,456};int count=0,i=0;while(k[i]){ if(k[i]%2==0||k[i]%5==0)count++;i++; }printf("%d,%d/n",count,i);}则程序段的输出结果为A.7,8B.8,8C.7,10D.8,10
[单选题]现有如下程序段#include "stdio.h"main( ){ int a[5][6]={23,3,65,21,6,78,28,5,67,25,435,76,8,22,45,7,8,34,6,78,32,4,5,67,4,21,1};int i=0,j=5;printf("%d/n",*(&a[0][0]+2*i+j-2));}则程序的输出结果为A.21B.78C.23D.28
[单选题]现有如下程序段#include "stdio.h"main(){ int a[5][6]={23,3,65,21,6,78,28,5,67,25,435,76,8,22,45,7,8,34,6,78,32,4,5,67,4,21,1};int i=0,j=5;printf("%d/n",*(&a[0][0]+2*i+j-2));}则程序的输出结果为A.21B.78C.23D.28
[单选题]现有如下程序段#include "stdio.h"main(){ int a[5][6]={23,3,65,21,6,78,28,5,67,25,435,76,8,22,45,7,8,34,6,78,32,4,5,67,4,21,1};int i=0,j=5;printf("%d/n",*(&a[0][0]+2*i+j-2));}则程序的输出结果为A.21B.78C.23D.28
[单选题]有如下程序段#include "stdio.h"main(){ int k[10]; int j; for(j=0;j<10;j++) scanf("%d",&k[j]); for(j=9;j> =0;j--) printf("%d",k[j]);}则程序段实现的功能是A.输入10个数据的顺序输入并输出 B.输入10个数据的逆序存放C.输入10个数据的逆序输出D.以上叙述均错误