#include<stdio.h>
main()
{ int a[]={1,2,3,4,5,6,7,8,9,0},*p;
p=a;
printf("%d/n",*p+9);}
A.0
B.1
C.10
D.9
[单选题]下面程序的输出结果是#include<stdio.h>main(){ int a[]={1,2,3,4,5,6,7,8,9,0},*p;p=a;printf("%d/n",*p+9);}A.0B.1C.10D.9
[单选题]以下程序的输出结果是#include<stdio.h>main(){int a=15,b=21,m=0;switch(a%3){case 0:m++;break;case 1:m++;switch(b%2){ default:m++;case 0:m++;break; } }printf("%d/n",m);}A.1B.2C.3D.4
[单选题]下面程序的输出结果是()。#include<stdio.h>main(){ int a[4][5]={1,2,4,-4,5,-9,3,6,-3,2,7,8,4};int i,j,n;n=9;i=n/5;j=n-i*5-1;printf("a[%d][%d]=%d/n",i,j,a[i][j]); } 执行后输出结果是( )。A)a[1][3]=6 B)a[1][3]=-3C)a[1][3]=2 D)不确定
[单选题]下面程序的运行结果是#include<stdio.h>main(){int a=28,b;char s[10],*p;p=s;do{b=a%16;if(b<10) *p=b+48;else *p=b+55;p++;a=a/5;}while(a>0);*p=′/0′;puts(s);}A.10B.C2C.C51D./0
[单选题]下面程序的运行结果是#include<stdio.h>main(){int a=28,b;char s[10],*p;p=s;do{b=a%16;if(b<10) *p=b+48;else *p=b+55;p++;a=a/5;}while(a>0);*p=′/0′;puts(s);}A.10B.C2C.C51D./0
[单选题]下面程序的输出结果是 #include <stdio.h> main(){ int i=2; printf("%d",f(i,i+1) ); } int f(int a,int b) { int c; c=a; if(a>b) c=1; else if(a==b) c=0; else c=-1; return(c);}A.-1 B.0 C.1 D.2
[单选题]下面程序的输出结果是#include<stdio.h>#include<string.h>main(){ char *p1="abc",*p2="ABC",str[50]= "xyz";strcpy(str+2,strcat(p1,p2));printf("%s/n",str);}A.xyzabcABCB.zabcABCC.xyabcABCD.yzabcABC
[单选题]以下程序的输出结果是#include<stdio.h>int fun(int n,int *s){ int f1,f2;if(n==0||n==1)*s=1;else{ fun(n-1,&f1);fun(n-2,&f2);*s=f1+f2;} }void main(){ int x;fun(6,&x);printf("/n%d",x);}A.7B.13C.9D.10
[试题]以下程序的输出结果是 ( 8 ) 。#include<stdio.h>main(){int i,j,sum;for(i=3;i>=1;i--){sum=0;for(j=1;j<=i;j++) sum+=i*j;}printf("%d/n",sum);}
[试题]以下程序的输出结果是 ( 9 ) 。#include<stdio.h>main(){ int j,a[]={1,3,5,7,9,11,13,15},*p=a+5;for(j=3;j;j--){ switch(j){ case 1:case 2:printf( " %d " ,*p++); break;case 3:printf( " %d " ,*(--p));}}}