怎么让下面这段代码在前台显示3行2列
<div class="top82">
<%set rsp=server.CreateObject("adodb.recordset")
rsp.open "select top 6 * from BigClass Order By BigClassID desc",conn,1,1
if rsp.eof then
response.write "没有类别!"
else
%>
<%while not rsp.eof %>
<div class="class">
<div style=" font-size:14px; font-weight:bold;"><p><%=rsp("BigClassName")%></p></div>
<%set rss=server.CreateObject("adodb.recordset")
rss.open "Select * From Product Where BigClassName='" & rsp("BigClassName") & "'",conn,1,3
if rss.eof then
response.write "没有该类产品!"
else
%> <%while not rss.eof %>
<div class="smallclass"><a href="productshow.asp?ArticleId=<%=rss("ArticleId")%>" target="_blank"><%=rss("Title")%></a></div>
<%rss.movenext
wend %>
<%end if%>
<%rss.close
set rss=nothing%>
</div>
<%rsp.movenext
wend %>
<%end if%>
<%rsp.close
set rsp=nothing%>
</div>
</div>
</div>
[单选题]看下面这段代码:My看下面这段代码: <IMG nClick=over(this) title=放大 src=URL align=left vspace=10 hspace=20>My Face!<br> It is always<br> smiling.<br> Hahaha…<br> 输出的结果是( )。A.B.C.D.
[问答题] 下面这段代码输出什么?为什么?
[试题]下面这段代码有错误么?switch (i){case():C.aseZero();break;case 1:C.aseOne();break;case 2:dufault;C.aseTwo();break;}
[试题]下面这段代码有错误么?switch (i){case(): 答://case()条件不能为空C.aseZero();break;case 1:C.aseOne();break;case 2:dufault;
[多选题] 下列选项中可以替换下面代码中第2行的等价代码有()。A . Final int k = 4;B . Public int k = 4;C . Static int k = 4;D . Private int k = 4;E . Abstract int k = 4;F . Volatile int k = 4;G . Transient int k = 4;H . Protected int k = 4;
[试题]下面这段代码输出什么?为什么?int i=5;int j=5;if (Object.ReferenceEquals(i,j))C.onsole.WriteLine("Equal");elseC.onsole.WriteLine("Not Equal");
[主观题]What’s the final result?(下面这段代码的最终运行结果是什么)double expectedValue = 1/2;if(expectedValue > 0){expectedValue = expectedValue + 0.5;}C.onsole.WriteLine(expectedValue);
[主观题]下面这段代码输出什么?为什么?int i=5;int j=5;if (Object.ReferenceEquals(i,j))C.onsole.WriteLine("Equal");elseC.onsole.WriteLine("Not Equal");//不相等,因为比较的是对象
[主观题]下面这段代码输出什么?为什么?int i=5;int j=5;if (Object.ReferenceEquals(i,j))C.onsole.WriteLine("Equal");elseC.onsole.WriteLine("Not Equal");
[填空题] 出纳在前台领取封包时,需要在()。