A .=24H
B . A.=42H
C . A.=40H
D . A.=00H
[问答题] 已知程序段如下:MOV AX,1234H;(AX)=1234H,标志位不变MOV CL,4;(AX)和标志位都不变ROL AX,CL;(AX)=2341H,CF=1,SF和ZF不变DEC AX;(AX)=2340H,CF=1不变,SF=0,ZF=0MOV CX,4;(AX)和标志位都不变MUL CX;(AX)=8D00H,CF=OF=0,其它标志无定义INT 20H程序结束时,AX和DX的内容是什么?
[填空题] 如果DPTR=507BH,SP=32H,(30H)=50H,(31H)=5FH,(32H)=3CH,则执行下列指令后:POP DPHPOP DPLPOP SP则:DPH=(),DPL=(),SP=()
[单选题]执行以下程序后,A中的值是();MOVA,#24H;ORLA,#0F0H;SWAPA;A .24HB .4FHC .F4HD .F2H
[单选题]有如下程序段#include "stdio.h"typedef struct aa{ int a; struct aa *next;} M;void set(M *k,int i,int *b){ int j,d=0; for(j=1;j<i;j++) { k[j-1].next=&k[j]; k[j-1].a=b[d++]; } k[j].a=b[d];}main(){ M k[5],*p; int d[5]={23,34,45,56,67}; set(k,5,d); p=k
[单选题]现有如下程序段#include "stdio.h"main(){ int k[30]={12,324,45,6,768,98,21,34,453,456};int count=0,i=0;while(k[i]){ if(k[i]%2==0||k[i]%5==0)count++;i++; }printf("%d,%d/n",count,i);}则程序段的输出结果为A.7,8B.8,8C.7,10D.8,10
[单选题]现有如下程序段#include "stdio.h"main(){ int k[30]={12,324,45,6,768,98,21,34,453,456};int count=0,i=0;while(k[i]){ if(k[i]%2==0||k[i]%5==0)count++;i++; }printf("%d,%d/n",count,i);}则程序段的输出结果为A.7,8B.8,8C.7,10D.8,10
[单选题]现有如下程序段#include "stdio.h"main( ){ int a[5][6]={23,3,65,21,6,78,28,5,67,25,435,76,8,22,45,7,8,34,6,78,32,4,5,67,4,21,1};int i=0,j=5;printf("%d/n",*(&a[0][0]+2*i+j-2));}则程序的输出结果为A.21B.78C.23D.28
[单选题]现有如下程序段#include "stdio.h"main(){ int a[5][6]={23,3,65,21,6,78,28,5,67,25,435,76,8,22,45,7,8,34,6,78,32,4,5,67,4,21,1};int i=0,j=5;printf("%d/n",*(&a[0][0]+2*i+j-2));}则程序的输出结果为A.21B.78C.23D.28
[单选题]现有如下程序段#include "stdio.h"main(){ int a[5][6]={23,3,65,21,6,78,28,5,67,25,435,76,8,22,45,7,8,34,6,78,32,4,5,67,4,21,1};int i=0,j=5;printf("%d/n",*(&a[0][0]+2*i+j-2));}则程序的输出结果为A.21B.78C.23D.28
[单选题]有如下程序段#include "stdio.h"typedef union{ long x[2]; int y[4]; char z[8];}atx;typedef struct aa { long x[2]; int y[4]; char z[8];} stx;main(){ printf("union=%d,struct aa=%d\n",sizeof(atx),sizeof(stx));}则程序执行后输出的结果是A.union=8,struct aa=8 B.union=8,str