关系（Relation）

[试题]In relation to the courts’ powers to interpret legislation, explain and differentiate between:(a) the literal approach, including the golden rule; and (5 marks)(b) the purposive approach, including the mischief rule. (5 marks)

[试题]In relation to company law, explain:(a) the limitations on the use of company names; (4 marks)(b) the tort of ‘passing off’; (4 marks)(c) the role of the company names adjudicators under the Companies Act 2006. (2 marks)

[试题]In relation to the law of contract, distinguish between and explain the effect of:(a) a term and a mere representation; (3 marks)(b) express and implied terms, paying particular regard to the circumstances under which terms may be implied in contracts

[单选题]The relation between the two paragraphs is that in the 2nd paragraph the author[A] challenges the viewpoint in the lst paragraph.[B] modifies his view expressed in the lst paragraph.[C] provides the reason for the argument in the lst paragraph.[D] fu

[单选题]（）is software about the relation between the customer and the supplier in marketing.A . B . CustomerRelationshipManagement（CRM）；C . D . CustomerService；；E . F . Salesplanning；；G . H . Distributionchannel

[单选题]在“LETC4=D4RELATION月WITH月+1”命令中，RELATION引导的内容含义为（）A .同表表页筛选条件B .他表表页筛选条件C .他表表页关联条件D .同表表页关联条件

[单选题]For relation where primary key contains multiple attributes，no non-key attribute should be functionally dependent on a part of primary key．This relation R is at least in (66) .(66) A．3NFB．2NFC．INFD．BCNF

[单选题]Let R and S be the relation respection respectively：Relation R:A B C Relation S:B C D1 2 3 2 3 46 7 8 2 3 59 7 8 7 8 1The number of tuples that the result of the expression R∞S(Here if natural join of relations R and S) is (69) ．(69) A．1B．4C．7D．10

[单选题]Let R and S be the relation respectively: Relation R: A B C Relation S: B C D 1 2 3 2 3 4 6 7 8 2 3 5 The number of tuplesthat the result of the expression R ∞ S (Here is the natural join of relations R and S) isA．3B．4C．6D．9

[单选题]F．or relation where primary key contains multiple attributes, no non-key attribute should be functionally dependent on a part of primary key. This relation R is at least in(66).A．3NFB．2NFC．INFD．BCNF