#include<stdio.h>
void fun(char **p)
{
++p; printf(“%s/n”,*p);
}
main()
{
char *a[]={“Morning”,”Afternoon”,”Evening”,”Night”};
fun(
A.;
}
程序的运行结果是( )。
A.Afternoon
B.fternoon
C.Morning
D.orning
[单选题]有以下程序#include <stdio.h>void fun(char *t,char *s){while(*t!=0) t++;while(*t++=*s++)!=0);}main(){char ss[10]=”acc”,aa[10]=”bbxxyy”;fun(ss,aA.; printf(“%s,%s/n”,ss,aA.;}程序的运行结果是( )。A.accxyy,bbxxyyB.acc,bbxxyyC.accxxyy,bbxxyyD.accbbxxyy,bbxxyy
[单选题]有以下程序#include<stdio.h>void fun(int n,int *p){int f1,f2;if(n==1||n==2) *p=1;else{fun(n-1,&f1); fun(n-2,&f2);p=f1+f2;}}main(){int s;fun(3,&s); printf(“%d/n”,s);}程序运行的结果为( )。A.2B.3C.4D.5
[单选题]有以下程序#include<stdio.h>void fun(int *a,int n)/*fun函数功能是将a所指的数组元素从大到小排序*/{int t,i,j;for(i=0;i<n-1;i++)for(j=i+1;j<n;j++)if(a<a[j]) { t=a;a=a[j];a[j]=t; }}main(){int c[10]={1,2,3,4,5,6,7,8,9,0},i;fun(c+4,6);for(i=0;i<10;i++) printf(“%d
[单选题]有以下程序#include <stdio.h>void fun(int *s,int n1,int n2){ int i,j,t;i=n1; j=n2;while(i<j) {t=s[i];s[i]=s[j];s[j]=t;i++;j--;}}main(){ int a[10]={1,2,3,4,5,6,7,8,9,0},k;fun(a,0,3); fun(a,4,9); fun(a,0,9);for(k=0;k<l0;k++)printf("%d",a[k]);
[单选题](21)有以下程序#include<stdio.h>main(){char *s=(“ABC);do{printf(“%d”,*s%10);s++;}while(*s);}注意,字母A的ASCII码值为65。程序运行后的输出结果是A.)5670 B)656667 C)567 D)ABC
[单选题]有以下程序:include<stdio.h>main( ){ char a[20],b[20],c[20];scanf("%s%s",a,b);gets(c);printf("%S%S%s/n",a,b,c);}程序运行时从第一列开始输入:This is a cat!<回车>则输出结果是( )。A.Thisisacat!B.Thisis aC.Thisis a cat!D.Thisisa cat !
[单选题]有以下程序:include<stdio.h>main( ){char s[]={"012xy"};int i,n=o;for(i=0;s[i]!=&39;0&39;;i++)if(s[i]>=as[i]<=z)n++;printf("%d/n",n);}程序运行后的输出结果是( )。A.0B.2C.3D.5
[单选题]有以下程序#include<stdio.h>main(){char s[]=“012xy\08s34f4w2”;int i,n=0:for(i=0;s[i]!=0;i++)if(s[i]>=‘0’&&s[i]<=‘9’)n++:printf(“%d\n”,n):}程序运行后的输出结果是A.0B.3C.7D.8
[单选题]有以下程序#include<stdio.h>main( ){char s[]=“rstuv”;printf(“%c\n”,*s+2);}程序运行后的输出结果是( )。A.tuvB.字符t的ASCII码值C.tD.出错
[单选题]有以下程序:include<stdio.h>main( ){ char a[5][10]={"one","tw0","three","four","five"};int i,j;char t: 、for(i=0;i<4;i++)for(j=i+1;j<5;j++)if(a[i][O]>a[j][0]){t=a[i][O];a[i][O]=a[j][O];a[j][O]