1)#include < iostream >
2)# include < math.h >
3)using namespace std;
4)double max(double x,doubley);
5)void main()
6){
7)double a,b,c;
8)cout << " input two numbers: ";
9)cin>>a>>b;
10)c=max(a,b);
11)cout<< " the squart of max imum="<< sqrt(c);
12)}
13)double max(doublex,doubley)
14){
15)if(x>y)
16)returnx;
17)else
18)returny;
19)}
若执行第9行时,输入89后按回车,则执行完第19行后,max函数的返回值是:()
A .8
B . 8.0(小数位数由编译器决定)
C . 9
D . 9.0(小数位数由编译器决定)
[单选题]1)#include < iostream >2)#include < cmath >3)using namespace std;4)double max(double x,doubley)5){6)if(x>y)7)return x;8)else9)return y;10)}11)int main()12){13)doublea,b,c;14)cout <<" input two numbers:";15)cin >>
[单选题]1)#include<iostream>2)usingnamespacestd;3)intmain()4){5)inta,b,result;6)cout<<"pleaseinputtwonumbers:";7)cin>>a>>b;8)result=3*a-2*b+1;9)cout<<"resultis"<<result<<endl;10)}程序第5行定义了几个整型变量:()
[单选题]有如下程序:#include<iostream>#include<iomanip>using namespace std;int main(){int S[]={123,234};cout<<right<<setfill(‘*’)<<setw(6);for(int i=0;i<2;i++){cout<<s[i]<<endl;}retum 0;}运行时的输出结果是A.123B.***123C.***123D.
[单选题]有如下程序:#include<iostream>#include<iomanip>using namespace std;int main(){cout<<setw(10)<<setfill(’X’)<<setprecision(8)<<left;cout<<12.3456793<<______<<98765;return 0;}若程序的输出是12.345679x98765xxxxx,则划
[单选题]有如下程序:#include<iostream>#include<cstring>using namespace std;class XCD{char*a;int b;public:XCD(char;l:aa,int bB){a=flew char[strlen(aA)+1];strcpy(a,aA);b=bb;}char*lE Geta(){return a;}int Getb(){return b;}};int main(){char*pl=”abcd”.*p2=”w
[单选题]有如下程序:#include<iostream>#include<cstring>using namespace std;class XCF{int a;public:XCF(int aa=O):a(aA){cout<<”1”;}XCF(XCF&X){a=x.a;cout<<”2”;}~XCF(){cout<<at}int Geta(){return at}};int main(){XCF dl(5),d2(d1);XCF半pd
[单选题]( 28 )有如下程序:#include<iostream>#include<cstring>using namespace std;class XCF{int a;public:XCF ( int aa=0 ) : a ( aa ) {cout<<"1" ; }XCF ( XCF& x ) {a=x .a; cout<<"2" ; )~XCF () {cout<<a;}int Geta () {return a;}};
[单选题]( 27 )有如下程序:#include<iostream>#include<cstring>using namespace std;class XCD{char* a;int b;public:XCD ( char* aa, int bb ) {a=new char[strlen ( aa ) +1];strcpty ( a,aa ) ;b=bb;}C.har* Geta () {return a; )int Getb () { return b;}};int main
[单选题]( 34 )有如下程序:#include<iostream>#include<iomanip>Using namespace std;int main(){int s[]={123, 234};cout<<right<<setfill('*')<<setw(6);for(int i=0; i<2; i++) { cout<<s[i]<<endl; }return 0;}运行时的输出结果是A. ) 123
[单选题]有如下程序:#include<iostream>#include<cmath>using std::cout;class Point{public:friend double distance(const Point &p); //P距原点的距离Point(int xx=0,int yy=0):x(xx),Y(YY){}//①private:int x,y;};double distance(const Point &p){ //②return sqrt(